òðóñèêè æåíñêèå óêðàèíà |
## Site planning and production calculations - Building ScienceTABLE OF CONTENTS INTRODUCTION .Obschaya Part 1 1.1 Purpose and working conditions specified details 1.2 Specifications for acceptance details 1.3 Material components and their characteristics 1.4 Analysis of technological design details Technological part 2 2.1 Type of production and its characterization 2.2 0predelenie exhaust stroke details 2.3 The choice of method blanks production 2.4 Determination of machining allowances 2.5 Calculating the size of the workpiece and the utilization of metal 2.6 Plan of Operations of the part 2.7 Selection of bases 2.8 Separation of operations on the installation and transitions 2.9 Selection of equipment for operations 2.10 Selection tools, cutting and measuring tools for Operations 2.11 The interim allowances and sizes 2.12 Calculation of cutting conditions on standards 2.13 Analytical calculation of cutting conditions on two diverse operations 2.14 Calculation of norms time for all operations, the establishment of discharges 2.15 "The economic rationale for the selected treatment option PART 3.KONSTRUKTORSKAYA 3.1 Designing a special cutting tool 3.2 Design of the measuring instrument 3.3 Design of machine tools for milling operations 4 INDUSTRIAL BALANCES AND SITE PLAN 4.1 Calculation of technological equipment and its load 4.2 Selecting the required amount of lifting and handling equipment 4.3 Calculation of the main and auxiliary workers 4.4 Calculation of production space, a description of the site plan 5 ORGANIZATIONAL PART 5.1 Organization of jobs and system maintenance 5.2 Measures for the Protection of the pile and Safety 5.3 Measures to save energy and metal 5.4 Determination of annual needs of materials, tools, energy and water ECONOMIC PART 6 6.1 Valuation of fixed assets 6.2 Determination of the cost of materials Determining the value of low-value 6.Z tools and equipment 6.4 Determining the value of all forms of energy and water 6.5 Definition of the payroll 6.6 Estimated costs of shop 6.7 Calculations costing shop cost per unit of output 6.8 Calculation of the cost-effectiveness of the project and the level of profitability 6.9 Technical and economic indicators section Output References Sheet comments normokontrolera Graphic materials Sheet 1 f A2 "Site Plan" Page 2 f A2 "Corpus" Page 3 f A2 "Body casting" Sheet 4l A1 "Map setup" Page 5 f A3 "Hand taps for metric thread" ? 6 A3 sheet "Fuses carving" Sheet 7 ft A1 "Tool milling" Sheet 8 p A1 "Tool milling" INTRODUCTION The Republic of Kazakhstan needs to raise and restore come in recent years in unsuitable equipment valves. In the presidential program "Kazakhstan-2030" for raising the economy of the Republic of Kazakhstan much attention is paid to raising and development of agriculture, as well as shut-off valve is an integral part of the equipment of agriculture, there is a need to create specialized repair shops shut-off valves on the ground. In this thesis work a project of specialized workshops that can produce the repair and overhaul of valves. With the creation of this workshop is to create new jobs, reduce costs for repair and maintenance of equipment. 1 GENERAL 1.1 PURPOSE AND WORKING CONDITIONS DETAILS GL 21003-100ASB housing is a basic part of the valve. The valve is a valve spindle, is screwed into the threaded nut fixed hodovoy- located in the cap or yoke. The use of threads, having the properties of self-braking, by leaving the plate valve in any position with the confidence that this situation will continue and will not spontaneously change under the pressure of the environment. Using thread allows the use of small efforts on the flywheel to control valve. The valve is simple to design and creates good conditions for reliable density at the closed position of the shutter. For these reasons, the valves got very widely used mainly in the shut-off valve. The valves are designed to work on pipelines and gas pipelines (water, steam, corrosive environments PN = 6 MPa (60kgs / cm2)) 1.2 TECHNICAL REQUIREMENTS FOR ACCEPTANCE DETAILS 1) You can surfacing 15x15 N9G2S Hb = 200 TU 2 078I-084-77 2) For valves with electric smelting to produce electrode CM-6L-5,0-2. 3) Unspecified casting radii up to 6 mm. 4) Unspecified tolerances of the holes on the H14 shafts h14 others - by ± (IT14 / 2) 5) At the end of the balance of profit traces autogenous cutting does not affect the thickness of the wall. PN40
6) for general release end balance of profit is allowed not handle. 100
7) marked with the type number 14 according to GOST 4666-75 mark of the manufacturer. 1.3 part material and its characteristics. Detail - GL21003-100ASV body is made of steel castings 25JI GOST 977-75 of the first group. For the manufacture of castings used basic or acid open-hearth or electric steel. The chemical composition shall conform to the requirements specified in Table 1. Table 1 - Chemical composition. Steel grade: C Mn Si P S Cr Ni Cu 25L 1050-74 0.22 0.35 0.30 - 0.90 0.20 - 0.52 0.06 0.06 0.30 0.30 0.30 1.4 Analysis of technological design details One of the most important factors that influence the nature of the process is the design manufacturability. Hull construction GL210Z 100 ASB complex configuration, but this design has convenient technological base that provide the required guidance and reliable fastening of the workpiece on the machine when its processing capabilities with multiple parties and a free supply of the instrument to the surface. The housing has a sufficient rigidity at which exclude the possibility of vibration during handling or excessive deformations of the cutting forces and the fastening. Technological part 2 2.1 TYPE OF PRODUCTION AND ITS CHARACTERISTICS The annual program statement valve GL 21003 - 100 ASB conditionally accepted 35000 pieces Given the weight of the part and the annual program, the type of production is determined by the ratio KZ.O. = Q / PM = 8/7 = 1.14; Q- where the number of different operations; RM- number of jobs that are running these operations, High-volume production. In large-scale production for each workstation attached one operation, which is carried out for a long time without a changeover to other operations using special equipment. Special equipment is widely automates and mechanizes processes, in-line methods. Such work organization provides high performance and relatively low production costs. 2.2 0PREDELENIE exhaust stroke PARTS The value is calculated based on the measure adopted in the draft two-shift operation. Time - is the time interval over which periodically release of products made certain names and sizes. Tact is determined by the formula [7]: t =, where: t - exhaust stroke in minutes; Fy - actual annual fund operating time per hour .; N - annual program of manufacture of the product. t = = 6,88 m 2.3 CHOICE OF METHOD OF PRODUCTION BLANKS Guided by the design details, material specifications, - the scale of production and objectives, in order to save metal adopt the method of producing a green - casting in sand molds. This method is used for complex shaped workpieces. In today's manufacturing and technological process, the flask with the mold halves, custom-molding machines, come to build on the tables. At the same time the conveyor fed rods with rod section. Collected forms are filled with dogs. Metal flows from the furnace via ladles suspended. Further conveyor drenched form is transported to the cooling chamber and the knockout lattice, where the separation of the casting from the flasks and the moldable mixture. Dimensional accuracy of castings corresponds to I class. Casting requires molding core to form the internal cavities of [3]. 2.4.OPREDELENIE machining allowance Allowance is called a layer of metal to be removed from the surface of the workpiece during processing. Assign machining allowance body parts GL21003 - 100 ASB Mass m = 27,4 The largest size of 350 items Estimated size of the blank: Ap = bottom. ZOn + 2, Table 3.6 [4] where: Dr. -raschetny diameter of the workpiece; -rated Bottom diameter of the workpiece; Z0- general allowance for processing to one side. When processing the linear dimensions Hp = Nnom. + Zo, Table 3.7 [4] where: Hp - estimated size of the flat surfaces; Nnom. - The nominal size of the flat surfaces. ?230 + 2x4 = 238 mm ?115 - 2x4 = 107 mm ?100 - 2x4 = 92 mm l 20 4 = 24 mm l 19 4 = 23 mm 350 l + 4 x2 == 358mm Tolerances, ie, deviations for billets GOST I855-55 and AINO 2009-55: ?238 + 2 = 240 mm + 358 mm l 2 = 360 mm ?107 - 2 == 105 mm ?92-2 = 90 mm l 1 = 24 mm 25mm l 1 + 23 mm = 24 mm 2. Calculation of the size 5 Billets and metal recovery The shape of the workpiece - a figure complicated configuration. Harvest volume is determined from the plus-tolerances, which divide the figure by 8 elementary geometric solids: F1 = (P2 r2) p = (107,52-572) p = 25, 918.14; V1 = F · h = 25 ? 25 = 918.14 669 657.3; F2 = (P2 r2) p = (1202- 502) p = 37 384, 95; V2 = F · h = 22 = 37 384,95x. 834 383.2; F3 = (P2-r2) p = (8I2- 502) p = 12 758; V3 = F · h = 12 758 x 8 = I23 432,1; F4 = (P2-r2) p = (65 ^ 45 ^) p = 6 911.5; V4 = F · h == 6 911,5 x 23. 168 = 964.5; F5 = (P2-r2) p = (87,52- 52,52) p = 15393, 82; \ / 5 = F · h = 15 393,82 x 40 = 636 753.3; _ F6 = (P2-r2) p = (602- 502) x 0,7854 = 3455,76; V6 = F · h = 3455,76 x 110 = 401,345, 2; F7 = (P2-r2) p = 0,7854 (I302- 1202) = 1963,5 x. 4 = 7854; V7 = F · h = 7854 x 120 = 973,860; F8 = (P2-r2) p = (752.- 502) p = 9 817.47; V8 = F · h = 9817,47 x 20 = 196 349.4; Vobsch- 669 657.2 + 834 383.1 + 123 432.1 + 168 964.5 + 636 753.5 + 401 345,2+ + 973 860.3 + 196 349.4 = 4 004745.3 G = Y · V3 = 0,00785 x 4004 745.3 = 31.450 kg Since when calculating the volume of the workpiece can not account for all casting radii, gradients, round off, then take them equal to 20% of the total weight of the workpiece DS = + 31.450 = 37.74 kg Utilization rate of materials is [4]: Ki.m. = Su: Cs; Ki.m. = 27.4: 37.74 = 0.73. 2.6 PLAN DETAILS processing operations 05 Operation Drill - molding machines 10 Operation milling - GF 14 00 15 Operation Turning - MK 112 Operation 20 machine gun - I B 284 25 Operation surfacing - VKSM - 1000 RB - 301 30 Operation automaton - 1B 284 35 Operation aggregate - 1 AMI 443 40 Operation locksmith 45 Operation Control 2.7 SEPARATION OF OPERATIONS FOR THE INSTALLATION AND TRANSITIONS 05 Operation Drill - casting 10 Operation Milling - machine GF 1400 Please refer to the TB. 1. Set .Remove item. 2.Frezerovat casting profit 15 Operation Turning - Machine GF 1400 Follow the instructions for TB. 1.Set, removing, 2 .Tochit simultaneously two flange ? 230 mm and 350 mm l trim on both sides. 20 Operation of machine-gun - machine 1B284 Soblyudat- instructions T B. 1.Set, removing. 2.Podrezat end ? 215 mm. 3.Tochit ? 115 mm. t = ZMM-blank. ? 124 mm 4.Tochit blank. 5 .Remove chamfer on the surface ? 215 mm. 6.Podrezat end ? 215 mm, sharpening ? 135 mm at point blank range. 25 Surfacing - VKSM - 1000 RB - 301 Please refer to the TB. 1.Set, removing. 2 Overlap surface ? 124mm h = b mm. 30 Operation of machine-gun - machine 1B284 Observe the safety instructions. 1.Set, removing. 2.Tochit surface ? 124mm, 3.Tochit groove ? 113 mm t = 4 mm 4 .Tochit ? 120 mm. 5.Tochit ? 100 mm. 6.Tochit ? 120 mm. 35 Operation aggregate - machine 1AMO 443 Please refer to the TB. 1.Set, removing. 2.Sverlit 8 holes ? H4mm. 3.Sveryait 8 holes ? 23mm. 8 countersink holes ? 18mm. 8 drill holes ? 23mm. 4.Narezat thread MI6 step 2 to 8 holes. 40 Operation locksmith - workbench Please refer to the TB. 1.Zachistit burr after porting. 2.8 SELECTION OF BASES Called base surface, replace it with a set of surfaces, the axis, the workpiece or assembly unit, in relation to which other components are oriented products come workpiece surface, processed or collected on this operation, Group design bases constitute the main and auxiliary base, which account in the design (choosing the shape of the surface, their relative positions, dimensioning, design standards of accuracy, etc.) is essential. The main base determines the position of the part or assembly unit in the product, and auxiliary baza- position of the connecting parts or assembly unit with respect to the part. Technological base called surface defining the position of a part or assembly unit during the manufacturing process. Machine Planing GF I400. Basing the workpiece is made by flanges ? ? 240mm and 215mm flange. (Prism) MK 112 machine. Basing made the holes ? 100 mm. (Cams) 1B 284 machine. Basing on the two flanges made ? ? 230mm and 215mm flange. (Cams) Machine 1AMO 443 Bazirovanie- two flanges ? 230 mm. (Prism) 2.9 SELECTION OF EQUIPMENT ON OPERATIONS 10 Operation milling On offer milling operations take Planing a special machine model GF 1400 C16H8. The machine is designed for milling profits simultaneously from three sides in detail GL 21003 - 100 ASB. Material Details Steel GOST 251-11 977-75. Basic data of the machine GF 1400: Table working surface dimensions according to GOST 6955-70: width 500mm length 1250mm Maximum table travel 1250mm Number of table feeds 18 Limits table feeds 20-1000 mm / min Rapid traverse table 4500mm / min The number of horizontal spindles 2 Number of vertical spindles 1 The greatest movement of spindle quill: 1 spindle 200mm 2 spindle 200mm 3 spindle 200mm The distance from the surface of the table to the end vertical spindle 30-550 mm Number of spindle speed: 1 spindle 19 2 spindle 19 3 spindle 19 Limits of spindle speeds: 1 spindle 25-1600 rev / min 2shpindel 25 - I600 / min 3 spindle 25-1600 / min Overall dimensions: length 4290mm width 3425mm height 2900mm Drive power kW 7,5h3 Machine weight 13100 kg Price 186,710 tenge Operation 15 machine gun, turning On turning operations offer to take special flange lathe MK 112. Basic data of the machine: Maximum diameter of workpiece over bed -40vmm, distance between centers 710mm The length of treatment with one caliper 640mm Spindle speed 12,5-2000vb / min Limits of working feeds: 7-4,16 longitudinal 0.0 mm / rev cross 0,04-2,08mm / v Machine dimensions: width 2010mm length 2522mm height 1324mm Machine weight 2178kg Drive power 7.5 kW 20 Operation automaton On turning operations offer to take six lathe spindle vertical semi-automatic model 1B284. Basic data of the machine: The largest diameter of the installed product passing over the guide when you turn the table Z6Omm The largest diameter of the installed product on a round bottom of the column 548mm Spindle diameter 470mm Number of spindles 6 The greatest vertical movement of the caliper 200mm Machine dimensions: length 3285mm width 2987mm height 4040mm Machine weight 15000kg Price 115,430 tenge Calipers; The greatest number of supports on the machine 5 Number of carriages of various kinds: simple vertical caliper 1 Caliper sequential steps of adjustment Universal Caliper Caliper drill head Number of steps 22 innings Rpm 20-224 Feed per revolution of the spindle 0,08-5,00mm Duration table rotation 3.4 seconds Power LP kW 25 Operation surfacing BKCM-IOOO RB-301 30 Operation automaton 1B284 35 Operation aggregate On an aggregate operation offer to take a three-pronged horizontal drilling and threading spindle 40 with four-position rotary table machine model IAM0443. Operations: drilling, countersinking, threading. Basic data of the machine: Machine dimensions: length 6350mm width 4860mm height 2500mm Machine weight 23000kg Price 150,798 tenge Main motor power motion 30kW Table 1. Power UM2464-011 with spindle box horizontal layout course of moving parts unit 500mm spindle box: envelope 800h720mm number of spindles 8 main motor power movement 5,5kBt Table 2. Power UM2474-012 with spindle box horizontal layout course of moving parts unit 800mm spindle box: envelope 1200h720mm number of spindles 24 main motor power movement 17,0kVt Table 3. Power 5U4651S with spindle box horizontal layout course of moving parts unit 400mm spindle box: envelope 800h720mm number of spindles 8 main motor power movement of 7.5 kW 2.10 SELECTION devices. Cutting and measurement equipment ON OPERATIONS 10 Operation milling machine GF 1400 To hold the workpiece GL 21003-100ASB "The valve body is" designed single pneumatic device. The workpiece is mounted on rigid supports and inclined plane of the prism strips. Clamp the workpiece by turning the handle pneumatic crane to '' hold 'by sticking leverage self-aligning, Finished part is removed from the device. Cutting tool: Face cutter ? 160mm Standard Face cutter ? 250mm Standard The tool measuring: Caliper 11-250-01 GOST 166-80 15 Operation Lathe MK 112 Fitting: Insert PRK320 Cutting tool: Cutter GOST 18877-73 2102-0059 T5K10 Cutter Criminal 2I30-40I5 Measuring tools: Caliper 11-250-01 GOST 166-80 Bracket 230mm ? n 14 STP 1742 163-83 ? 230mm bracket Criminal 8II3-4003 / 2 20 Operation automaton 1B284 Fitting: chuck model 425P Cutting tools: 1.Rezets 10C2573 (20h32h100) 2.Rezets 1032100-0226-IOO T5K10 STP 21004-74 3.Rezets 1032101-0894-65T5K10 STP 21013-74 4.Rezets 12C-C2573 (16h16h65) 5.Rezets 11-S2573 (16h16h75) GOST 18877-73 6.Rezets 2102-0060 7.Rezets 10-S2573 (20h32h100) 8.Rezets 1032100-0226-100 T5K10 STP 21004-74 Measuring tools: Caliper ShTs-11-250-0,1 GOST 166-80 Caliper ShTs -1-125-0.1 GOST 166-80 Cork ?115mm N14PR STP 0742.172-83 Cork ?115mm N14NE STP 0742.173-83 Cork ? 94mm N14PR STP 0742.172-83 Cork ? 94mm H14 NOT STP 0742.173-83 25 Operation surfacing BKSM- 1000 RB-301 30 Operation automaton 1B284 Fitting: chuck model 425P Cutting tools: Criminal 1.Rezets 2102-4010 (16h16h70) Criminal 2.Rezets 2102-4010 0 (16h16h70) Criminal 3.Rezets 2102-4011 (16h16h75) Criminal 4.Rezets 2102-4009 (16h16h70) 5.Rezets 5S2808 (16h16h70) 6.Rezets 13C2573 (16h16h85) 7.3enker 2329 Criminal Code 4005-01 Measuring tools: Caliper ShTs-11-250-0.1 GOST 166-80 Cork ? 140mm STF N12PR 0742-172-83 Cork ? 140mm STF N12NE 0742-173-83 Caliper ShTs 1-125-01-GOST 166-80 Cork 0 N14PR 100mm STF 0742-172-83 Cork 0 H14HE 100mm STF 0742-173-83 Template Criminal 8424-4199 Template Criminal 8424-4200-01 35 Operation Machine 1AM0443 Device when the machine IAM0443-050 Cutting tools: ? 14mm drill GOST 12121-77 2301-3439 ? 23mm drill GOST 10903-77 2301-0079 Tap M1b 2620-1619N2 GOST 3266-71 Measuring tools: Cork ? 14mm HI2 STP 0742.169-83 Cork ? 23mm HI5 STF 0742.169-3 Cork GOST 17756-72 8221-0068 7H Cork 822I-1068-7H GOST 17757-72 40 Operation locksmith Grinding machines IP2013 Grinding PP 60h25h20 GOST 2424-75 GOST 71465-69 Files 2822-0024 2.11 The interim allowance for processing Calculation of allowance for processing the inner surface 140 ? + 0.40 D = 0.7 ± 1 mm / mm rzagot. DUxL = 0,7x = 350 = 245 m RAfter roughing = 245 x 0,06 = 14,7mkm RAfter finishing = 14,7 x 0,05 = 0,74mkm Because of the small value of r after finishing miss, Ku = 0.06 Ku = 0.05 eu = eb + eZ eb = 0 eu1 = 140 eu2 = 140 x 0.06 = 8.4 EAfter finishing = 8,4 x 0,05 = 0,42 Tolerances: 400 - general admission to drawing 460 - Annex 3 2000 - Table 3.3 Estimated allowances Ziminpo clean. 2 = (R · Zi-1 + Ti-1 + r2i-e2u + 1) Zimin = 2 (+ 100 + 100) = 429; Ziminpo black. = 2 (250 + 250 + = 2 = (+ 500) = 1490; Estimated size after roughing and maximum size limit Estimated nominal plus the minimum allowance 140 + 0.429 = 140.429 Estimated size after finishing Estimated size after roughing minus the estimated allowance: 139.57 - 1.49 = 138.08 The minimum size limit Limiting the maximum size of minus tolerance: after finishing 140 - 0.4 = 139.6 after rough 139.57 - 0.46 = 139.11 workpiece 138.08 - 136.08 = 2.0 The maximum allowance after roughing The minimum size limit after finishing minus the size limit after the draft: 139.6 - 139.11 = 0.49 mm = 490 mm 139.11 - 136.08 = 3,030mm = 3030 mm Minimum allowances The maximum size limit after finishing minus the maximum size limit after roughing: 140 - 139.57 = 0.43 mm = 430 mm 139.57 -138.08 = 1.49 mm = 1490 mm Verification: d1- d2 = 2000 - 460 = 1540; Zimin- Zimax = 3030 - 1490 = 1540; 1540 = 1540. Linear dimension 20-0,84 r and e tezhe data Ziminposle finishing = R · Zi-1 + Ti-1 + ri-1 + Eu = = 100 + 100 + 14.7 = 214.7 Ziminposle rough = 250 + 250 + 245 + 8.4 = 753.4 Estimate the size and the minimum size limit after finishing 20 - 19.16 = 0.84 after rough 19.6 + 0.21 = 19.37 workpiece 19.37 + 0.75 = 20.12 Limiting the maximum size Estimated size plus tolerance: 19.16 + 0.4 = 19.56 19.37 + 0.46 = 19.83 20.12 + 2.0 = 22.12 The maximum allowance The maximum size limit of the workpiece minus the maximum size limit after roughing: 22.12 - 19.83 = 2.29 The maximum size limit after roughing minus the maximum size limit after finishing: 19.83 - 19.56 = 0.27 Minimum allowance The minimum size limit of the workpiece minus the minimum size limit after roughing: 20.12 - 19.37 = 0.75 19.37 - 19.16 = 0.21 Verification: d1- d2 = 2000 - 460 = 1540; Zimin- Zimax = 3030 - 1490 = 1540; 1540 = 1540. Table 2.- payment of allowances, tolerance and inter-operational dimensions on technological transitions. Analytical method of calculation. Technological operations and transitions processing individual surfaces Elements allowance, m Calculated allowance Z, m Calculated Tolerances microns in size limits Limit allowances R zi-1 T i-1 r i-1 e at max min Z imax Z imin The inner surface 140 ? 0 0.4 Harvesting, casting 250250245200 - 2000 138.08 138.08 136.08 Turning rough 100 100 14.7 12 1490 139.57 460 139.57 139.11 1490 3030 Finish turning 25 25 - - 430 140 400 140 139.6 430 490 Linear dimension of 20 -0.84 Harvesting, casting 250 250 245 140 20.12 2000 22.12 20.12 Boring roughing 100 100 14.7 8.4 753.4 19.37 19.83 19.37 360 750 2290 Boring finishing 25 25 - - 214.7 19.16 840 19.56 19.16 270 210 2.12 Calculation of cutting conditions according to the standards 10 Operation milling Determining the length of the stroke at each transition 1. milled casting profit [8] L BC = L + l1 = 160 + 70 = 230 mm 2. milled casting profit L BC = L + l1 = 215 + 130 = 345mm 3. milled casting profit L BC = L + l1 = 160 + 70 = 230 mm Depth of cut t1 = ZMM t2 = ZMM t3 = ZMM Assign supply for each transition [8]. S1 = 0,24 S2 = 0,24 S3 = 0,24 As we take the calculated value for each transition S minute under the directory [8] SM1 = 160 mm / min SM2 = 160 mm / min SM3 = 160 mm / min Assign speed [8] V1 = 80 m / min V2 = 125 m / min V3 = 80m / min Find the speed of each spindle n1 = 1 000 * V / p D = 1000 * 80/160 = 3.14 * 160 rev / min n2 = 1000 * V / p D = 1000 * 125/215 * 3.14 = 160 rev / min n3 = 1 000 * V / p D = 1000 * 80/160 = 3.14 * 160 rev / min Cutting power [8] N1rezaniya = 5.6 N2rezaniya = 6.4 N3rezaniya = 5.6 .Use Power factor of the machine KN = Nras / nst = 17.6: 22.5 = 0.78 Nras = Nrez / h = 17,6: 0,8 = 22 15 Operation Turning MC 112 Determining the length of stroke [4] 1. L AD = 162 - 100/2 = 31 mm l1 = 6 mm; L BC = 31mm + 6mm = 37 mm 2. L AD = 22mm + 6mm = 28 mm 3. L AD = 31mm + 6mm = 37 mm 4. L AD = 22mm + 6mm = 28 mm Depth of cut t1 = 5mm t2 = 5mm t3 = 5mm t4 = 5mm Assign supply for each transition S1 = 0,23 S2 = 0,23 S3 = 0,23 S4 = 0,23 Assign speed [8] V = 148 Cutting speed prescribed with correction factors Knv- correction factor for the surface condition of the treated Knv- correction coefficient for the material of the cutting tool Knv = 0.5 Knv = 0.6 V = 148 x 0.5 x 0.6 = 44 m / min Find the speed of the spindle n = 1 000 * V / p D = 86 rev / min adjust the passport: n = 90 rev / min Assign speed by limiting the length of treatment V = p D n / 1000 = 3,14 * 160 * 90/1000 = 45 m / min. Determination of the power tool to [8] Cutter N1- Table. = 1.0 kW. when t = 5 mm S = 0,3 mm / rev Cutter N2- Table. = 1.0 kW. when t = 5 mm S = 0,3 mm / rev Cutter N3- Table. = 1.0 kW. when t = 5 mm S = 0,3 mm / rev Cutter N4- Table. = 1.0 kW. when t = 5 mm S = 0,3 mm / rev Aggregate capacity Nrez = N1 + N2 + N3 + N4 = 4 kW Determination of the adequacy of the power of the machine S Nrez ? Nshn, Nshn = nst · h, where: h = 0,8; Nst = 7.5 kW Nshn = 7.5 kW 0.8 kW = 6. <7.5 kW 4 kW. <6 kW. Capacity utilization rate of the machine K N = Nras / nst = 5: 7.5 = 0.65 Nras = Nrez / h = 4: 5 = 0.8 20 Operation automaton 1B 284 Determining the length of stroke Trim the butt RH L = 215 - 105/2 = 55mm l1 = 5mm L RH = 55 + 5 = 60 mm 1. Sharpen ? 125 L RH = 10 + 2 = 12 mm 2. Sharpen surface ? 94 RH L = 25mm 3. Sharpen surface ? 125 RH L = 25mm 4. Remove fazku RH L = 5mm 5. grind surface ? 215 RH L = 55mm Depth of cut 1. t = 3mm 2. t = 4mm 3. t = 6mm 4. t = 2mm 5. t = 2mm Assign supply for each transition [8] S1 = 0,28 mm / rev S2 = 0,2 mm / rev S3 = 0,2 mm / rev S4 = 0,2 mm / rev S5 = 0,28 mm / rev Assign speed [8] V = 148 mm / min Cutting speed prescribed with correction factors Knv- state correction factor treated surface Knv = 0.5; Knv- correction coefficient for the material of the cutting tool, Knv = 0.6. V = 148 x 0.5 x 0.6 = 44 m / min Find the speed of the spindle n1 = 1 000 * V / p D = 1000 * 44 / 3.14 = 65.8 * 215 rev / min Adjust the passport 63 rev / min 1. Vfakt = p D n / 1000 = 3,14 * 215 * 63/1000 = 42.5 m / min. 2. V2 = p D n / 1000 = 3,14 * 115 * 63/1000 = 22.7 m / min. 3. V3 = p D n / 1000 = 3,14 * 124 * 63/1000 = 24.5 m / min. 4. V4 = p D n / 1000 = 3,14 * 124 * 63/1000 = 24.5 m / min. 5. V5 = p D n / 1000 = 3,14 * 215 * 63/1000 = 42.5 m / min. Determining the total capacity of cutting [8] Cutter N1- Table. = 2.0 kW. when t = 3 mm S = 0,28 mm / rev Cutter N2- Table. = 2.0 kW. at t = 4 mm, S = 0,2 mm / rev Cutter N3- Table. = 2.0 kW. when t = 6 mm S = 0,2 mm / rev Cutter N4- Table. = 2.0 kW. when t = 2 mm S = 0,2 mm / rev Cutter N5- Table. = 2.0 kW. when t = 2 mm S = 0,28 mm / rev Determination of the power tool to [8] S Nrez ? Nshn, Nshn = nst · h, where: h = 0,8; Nst = 30kW Nshn = 30 kW 0.8 = 24 kW. <30 kW 10 kW. <24 kW. Capacity utilization rate of the machine For N = Nras / nst = 12.5: 30 = 0.41 Nras = Nrez / h = 10: 0.8 = 12.5 30 Operation automaton 1B284 Determine the length of the stroke at each transition [8] c4 1. l = 22mm l1 = 6mm L RH = 22 + 6 = 28 mm 2. L RH = 4mm 3. L RH = 14mm 4. L RH = 25mm 5. L RH = 25mm Depth of cut 1. t = 3mm 2. t = 4mm 3. t = 10mm 4. t = 3mm 5. t = 2mm Assign supply for each transition [8] S1 = 0,2 mm / rev S2 = 0,1 mm / rev S3 = 0,1 mm / rev S4 = 0,2 mm / rev S5 = 0,14 mm / rev Assign speed [8] V = 148 mm / min Cutting speed prescribed with correction factors Knv- correction factor for the surface condition of the treated Kuv- correction coefficient for the material of the cutting tool, K0v- correction factor for the processed material Knv = 0.5 Kuv = 0.6 K0v = 0.8 V = 148 x 0,5 x 0,6 x 0,8 = 35,52 m / min Cutting conditions assign respect to the limiting transition Slim- S6 llim- l6 n = 1 000 * V / p D = 1000 * 35/100 = 3.14 * 113.1 rev / min Adjust the passport n = 90 rev / min V1fakt = p D n / 1000 = 3,14 * 124 * 90/1000 = 31.1 m / min. V2 = p D n / 1000 = 3,14 * 113 * 80/1000 = 28.4 m / min. V3 = p D n / 1000 = 3,14 * 120 * 80/1000 = 30.1 m / min. V4 = p D n / 1000 = 3,14 * 100 * 80/1000 = 25.12 m / min. V5 = p D n / 1000 = 3,14 * 215 * 63/1000 = 30.1 m / min. Determination of total capacity on all instruments [8] N1 = 2,0 kW. when t = 3 mm S = 0,2 mm / rev N2 = 2,0 kW. at t = 4 mm, S = 0,1 mm / rev N3 = 2,0 kW. at t = 10 mm S = 0,1 mm / rev N4 = 2,0 kW. when t = 3 mm S = 0,2 mm / rev Cutter N5 = 2,0 kW. when t = 2 mm S = 0,28 mm / rev Aggregate capacity Nrez = N1 + N2 + N3 + N4 = 4 kW Determination of the adequacy of the power of the machine S Nrez ? Nshn, Nshn = nst · h, where: h = 0,8; Nst = 7.5 kW Nshn = 7.5 kW 0.8 kW = 6. <7.5 kW 4 kW. <6 kW. Capacity utilization rate of the machine K N = Nras / nst = 5: 7.5 = 0.65 Nras = Nrez / h = 4: 5 = 0.8 35 Operation aggregate Determining the length of the stroke at each transition I. / p. = ^ - ^ RH L = l + l1 = 28mm l = 20 mm l1 = 6mm RH = L + 20mm = 26mm 6mm 2. L = 31mm RH 3. L RH = 2mm 4. L RH = 31mm 5. L RH = 26mm Depth of cut 1. t = 7 mm 2. t = 11,5 mm 3. t = 9 mm 4. t = 11,5 mm 5. t = 2 mm Assign supply for each transition [8] S1 = 0,14 mm / rev S2 = 0,23 mm / rev S3 = 0,25 mm / rev S4 = 0,23 mm / rev S5 = 0,2 mm / rev Assign speed V1 = 24 m / min V2 = 32 m / min V3 = 32m / min V4 = 32 m / min V5 = 6 m / min Cutting speed to take the correction factor Knv- correction factor for the surface condition of the treated Knv = 0.6 24 * 0.6 = 14,4m / min n1 = 1 000 * V / p D = 1000 * 14.4 / 14 * 3.14 = 327.6 rev / min adjust the passport 275 rev / min V1 = p D n / 1000 = 3.14 * 14 * 275/1000 = 12 m / min n2 = 1000 * V / p D = 1000 * 14.4 / 23 = 3.14 * 194 rev / min adjust the passport 180 rev / min V2 = p D n / 1000 = 3.14 * 23 * 180/1000 = 12.1 m / min to countersink n3 = 1 000 * V / p D = 1000 * 14.4 / 18 = 3.14 * 254.8 rev / min adjust the passport 200 rev / min V3 = p D n / 1000 = 3.14 * 14 * 200/1000 = 11.3 m / min n4 = 1 000 * V / p D = 1000 * 14.4 / 23 = 3.14 * 194 rev / min adjust the passport 180 rev / min V4 = p D n / 1000 = 3.14 * 23 * 180/1000 = 12.1 m / min n5 = 1000 * 6/16 * 3.14 = 120 rev / min Determination of total power cut on all instruments [8] Drill N1 = 0,28 kW. when t = 7, S = 0,23 mm Drill N2 = 0,28 kW. when t = 7, S = 0,23 mm Drill N3 = 0,28 kW. when t = 7, S = 0,23 mm Drill N4 = 0,28 kW. when t = 7, S = 0,23 mm Drill N5 = 0,28 kW. when t = 7, S = 0,23 mm Drill N6 = 0,28 kW. when t = 7, S = 0,23 mm Drill N7 = 0,28 kW. when t = 7, S = 0,23 mm Drill N8 = 0,28 kW. when t = 7, S = 0,23 mm Aggregate capacity Nrez = N1 + N2 + N3 + N4 + N5 + N6 + N7 + N8 = 2,24 kW Determination of the adequacy of the power of the machine S Nrez ? Nshn, Nshn = nst · h, where h = 0,8; Nst = 5.5 kW Nshn = 5.5 kW - 0.8 = 4.4 kW. <5.5 kW 4.4 kW. <5.5 kW. Capacity utilization rate of the machine Nras = Nrez / h = 2,24: 0,8 = 2,8 N = Nras / nst = 2.8: 5.5 = 0.5 Determination of total capacity on all instruments Drill N1 = 0,378 kW. when t = 11,5 mm S = 0,23 Drill 16 pc. Aggregate capacity SNrez = N1 + N2 + N3 + ... + N16 = 6,048 kW Determination of the adequacy of the power of the machine S Nrez ? Nshn, Nshn = nst · h, where h = 0,8; Nst = 17kvt Nshn = 17 kW - 0.8 = 13.6 kW. <17 kW 6,048 kW. <13.6 kW Nras = Nrez / h = 6,048: 0,8 = 7,56 N = Nras / nst = 7.56 17 = 0.44 5 Spindle speed machine n = 1 000 * V / p D = 1000 * 14.4 / 23 = 3.14 * 194 rev / min Adjust the passport 180 rev / min. 10 Operation milling GF 1400 material - steel 25L II - GOST 977-75 Choosing a cutting tool - face cutter ? 250 mm with interchangeable plates pentagonal hard metal. Assign cutting conditions: 1. Depth of cut t = 3 mm. 2. Assign supply S = 0,24 m 1 tooth. 3. Assign tool life table 38 [13] T = 180 min 4. Determine the cutting speed in m / min permissible cutting properties cutters V = (CV * Dq / Tm * tx * Szyv * Buv * Zpv) * Knv = = (332 * 2500.2 / 1800.2 * 30.5 * 0,240,4 * 2300.2 * 120) * 0.8 = 96.3 n = 1 000 * V / p D = 1000 * 148.8 / 3.14 = 122.7 * 250 rev / min Adjust the passport 160 rev / min. 2.13 Analytical calculation of cutting conditions TWO dissimilar OPERATIONS 35 Operation aggregate machine 1AMO 443 material - steel 25L II - GOST 977-75 Choosing the cutter drill P18 - 23mm. Assign cutting conditions: 1. Depth of cut t = 11,5 mm 2. Assign supply S = 0,23 3. Assign the period of resistance Table 92 T = 50 min 4. Determine the cutting speed in m / min cutting properties permissible drill V = (CV * Dq / Tm * Sy) * Kv CV- constant cutting conditions for the data; D - diameter of the drill, mm; T - the period of resistance, min; K - correction factor for cutting speed. x, q, m, y - Exponents For a given processing conditions find tab. 28 [13] CV = 7; q = 0,40; m = 0,20; y = 0,50; Kv = 0,584 V = (7 * 3.62 / 2.19 * 0.479) = 0.584 * 14 m / min 2.15. CALCULATION standard time for all operations. ESTABLISHMENT OF DISCHARGE 10 Operation milling Set blank fix. Take Off. TV = 1.8 [9] Definition of computer time T1 = Lpx / Smin = 230/160 = 1.43 (min); T2 = 345/160 = 2.15 (min); T3 = 230/160 = 1.43 (min); T2 = 2.15 (min) - limiting; Tsht = (T0 + TCE) * (1 + (AGBU aotl +) / 100) where: K - universal equipment and semi-automatic (1.1) aobs.- time service workplace AGBU. = 4% of the operational time aotl. - Time to rest, and personal need aotl. = 4% of the operational time [9] Tsht = (2,15 + 1,8 * 1,1) + (I + (4 + 4) / 100) = 4.56 min. Tshk = Tsht * 0.8 * 0.8 = 4.56 = 0.36 min. Tshk = Tsht + QST = 4.56 + 0.36 = 4.92 min Assign IV discharge papers. 15 Operation Turning Set blank fix. Take Off. TV = 1.8 [9] Definition of computer time T1 = Lpx / Smin = 67 / 20.7 = 1.78 (min); T2 = 28 / 20.7 = 1.35 (min); T3 = 37 / 20.7 = 1.78 (min); T4 = 28 / 20.7 = 1.35 (min); T2 = 1.35 (min) - limiting; Tsht = (T0 + TCE) * (1 + (AGBU aotl +) / 100) where: K = 1,1 be the universal and semi-automatic equipment aobs.- time service workplace AGBU. = 6.5% of the operational time aotl. - Time to rest, and personal need aotl. = 4% of the operational time Tsht = 3.79 min. Tshk = 0.3 min. Tshk = 4.09 min Assign IV discharge papers. 20 Operation automaton 1B284 Set blank fix. Take Off. [9] TB = 1,2 [9] Definition of computer time T1 = Lpx / Smin = 67 / 17.64 = 3.4 (min); T2 = 25 / 12.6 = 1.98 (min); T3 = 25 / 12.6 = 1.98 (min); T4 = 5 / 12.6 = 0.39 (min); T5 = 55 / 3.11 = 14.49 (min); T1 = 3.4 (min) - limiting; Tsht = (T0 + TCE) * (1 + (AGBU aotl +) / 100) where: K = 1,1 be the universal and semi-automatic equipment aobs.- time service workplace AGBU. = 6.5% of the operational time aotl. - Time to rest, and personal need aotl. = 4% of the operational time Tsht = 5.21 min. Tshk = 0.41 min. Tshk = 5.62 min Assign IV discharge papers. 30 Operation automaton 1B284 Set blank fix. Take Off. [9] TB = 1,2 [9] Definition of computer time T1 = Lpx / Smin = 28/16 = 1.75 (min); T2 = 4/8 = 0.5 (m); T3 = 10/8 = 1.25 (m); T4 = 25/16 = 1.56 (min); T5 = 35 / 11.2 = 3.12 (min); T5 = 3.12 (min) - limiting; Tsht = (T0 + TCE) * (1 + (AGBU aotl +) / 100) where: K = 1,1 be the universal and semi-automatic equipment aobs.- time service workplace AGBU. = 6.5% of the operational time aotl. - Time to rest, and personal need aotl. = 4% of the operational time Tsht = 4.9 min. Tshk = 0.39 min. Tshk = 5.29 min Assign IV discharge papers. 35 Operation aggregate 1.AMO 443 Set blank fix. Take Off. [9] TV = 1.8 [9] Definition of computer time T1 = Lpx / Smin = 26 / 38.5 = 0.67 (min); T2 = 60 / 41.4 = 1.45 (min); T3 = 2 / 62.5 = 0.03 (min); T4 = 31 / 41.4 = 0.75 (min); T5 = 26/240 = 0.11 (min); T5 = 1.45 (min) - limiting; Tsht = (T0 + TCE) * (1 + (AGBU aotl +) / 100) where: K = 1,1 be the universal and semi-automatic equipment aobs.- time service workplace AGBU. = 6.5% of the operational time aotl. - Time to rest, and personal need aotl. = 4% of the operational time Tsht = 3.79 min. Tshk = 0,39min. Tshk = 4.09 min Assign IV discharge papers. 40 Operation locksmith Set the item. Take Off. [9] TB = 0.52 = 3.48 Tshk (min) T0 = ??2.96 Assign IV discharge papers. 2.16 ECONOMIC studies of the selected treatment option In the thesis project for turning operation piece machined 1B284, in the factory version - on 4 machines 1512. [15] Compare rates: 1512 1B284 The cost of the machine to rub .; 370000tenge (4 pcs) 23086 Motor power, kW; 880.kvt (4 pcs) 30 Piece time, hour; 0.86 0.993 Computer time, hour; 0.67 0.081 Cost per minute Operating instruments. 0.111 0.42 PART 3 Design 3.1.PROEKTIROVANIE special cutting tools The main structural elements are the tap cutting l calibrating part number; profile and direction of the grooves, the corners cut, thinning of the gauge, thread elements, completeness [11,12] In accordance with GOST specifies the nominal dimensions of the threaded connection: D, D1, D2, R, H, H1, R. Outer diameter D = 16mm The inner diameter D1 = 13,8350,3mm The average diameter D2 = 14,7010,132mm Step 2 P = ± 0.03 mm H = 0.87 P = 1.74 mm H1 = 0.54 mm F = 1.08 R = 0,14 F = 0.28 mm Limit size diameter nuts D2max = D2 + ES, where the upper deviation ES- D1max = D1 + ES, D2max = 14.701 + 0.132 = 14,833mm D1max = 13.835 + 0.3 = 14,135mm The diameter of the tap on the front end dT = D1- (0,1: 0,35) = 13.835 - 0.1 = 13,735mm The length of the cutting part of the tap lp1, = 6, P = 12mm Diameters for the tap d = D = 16 mm d2 = D2 = 14,701mm d2 = D1 + 0.055 P = 13.835 + 0.055 * 2 = 13,945mm Rear angle a = 100 The value zatylovaniya K = tga (p D / n) = 3.14 * 10 * 16/3 = 2.95 tgax (K n / p D) = 295 * 3/16 * 3.14 tgaN = tgax * sin 300 = 0.088; tgaN3 = tgax * sin 900- 5,4 = 0,175; The calculations angles These curves were plotted graphs of their changes. Good quality thread turns provided the optimum cutting conditions, the geometry of the tap, coolant composition and method of attachment of the tap. The machine used two methods of threading taps: samozatyagivanie without forced feeding and feeding on the copier. 3.2 Design of the measuring instrument Calculated the size of the executive caliber - plugs M16 - 7H STP 0742-192-84 for holes M 16 -2-H7 [6] 1) Determine the largest value of the average diameter of the hole, as it coincides with the nominal, then the table we find A2 = 14,701mm According to Table 5 for step 2 and ? 16mm find adopted the line number - 26. According to Table 6, we find the line number of the top 26 new caliber deviation is + 23mkm. Lower deviation of the new caliber is + 9mkm; maximum deviation worn equal caliber - 5 microns. The size of the new gauge plugs on the average diameter is 14.701 + 0.023 = 14.724 mm Admission is (23) - (0.9) = 14mkm Therefore, the tube size PR executive for the average diameter is equal to 14.724 - 0.014 The size limit is worn caliber 14.701 - 0.005 = 14.696 mm. 2) Determine the size of the plug PR executive from the outside diameter; need to know the greatest deviation limit of the inner diameter of the holes D. It coincides with the nominal, then D = 16mm. Then on Table II for. line 26, we find the upper deviation caliber, it is + 30MKM. Lower deviation gauge on the outer ? = + 2mkm. Maximum deviation worn caliber = - 5 microns. Admission is (30) - (2) = 28mkm Consequently, the size of the PR executive from the outside diameter is equal to 16.030 - 0,028mkm. Size limit worn gauge on the outside diameter 16.0 - 0.005 = 15,995mm. 3) To determine the size of the PR executive of the inner diameter is necessary to know the value of the limit of the smallest inner diameter of the hole D1 = 13.835 In Table 15 Upper deviation of the new caliber is 0, the lower deviation of the new caliber equal to -26 microns. Admission is -26mkm, executive tube size PR on the inner diameter is equal to 13.835 - 0.026 (mm) Bushing threaded plugs with the full make-up with the details set that error Da / 2 and DPn offset error of the mean diameter, and that the size of A is not less than the set limit size. The through traffic jams, so check the thread complex. Impassable plugs checks average diameters of the holes! and set the size DZne more to limits. Find the greatest value of the average diameter of the hole as it coincides with the nominal, then the table we find A2 = 14,966mm, according to Table 5 for step 2 and diameter of 16 find the line number, it is equal to 26. According to [6] to find the top 26 rows of the new gauge deviation is + 14mkm. Lower deviation cork is not 0, the limit deviation worn the same caliber - 8mkm. The size of the new executive caliber plug on the average diameter is 14.966 + 0.014 = 14,980mm Size extremely worn-caliber equal to 14,980 - 0,008 = 14.973 4) Determine the executive tube size is not on the outside diameter. Need the most extreme deviation of the internal diameter of the hole D = 15.387. According to Table II, line number 26, we find the upper deviation caliber, it is + 21mkm. Marginal-worn U = 7 mm Admission is (+ 21mkm) - (7 mm) = 28mkm Consequently, the size of the executive on the outside diameter is equal to 15.387 - 0.028 = 15,359mm 5) To determine the size of the PR executive of the inner diameter is necessary to know the value of the smallest hole diameter DR = 13.835 According to Table 15, the lower deviation of 7 mm, executive tube size 13.835 - 0.007 = 13,828mm 3.3 DESIGN FOR Machine-tool milling operations Develop a single device with pneumatic clamping parts for milling and casting profits with flanges. Selecting the method of installation (based) components and placing positioning elements in the adaptation, determine the amount, location and direction of application of forces to clamp. Define the cutting force in milling by the formula [18] PZ = [(10 * CP * tx * Syz * Vi * Z) / dq * nw] * CMR [13] where: Sp- constant cutting conditions for the data; t - milling depth, mm; S - feed per tooth cutter, mm; B - milling width, mm; Z - the number of teeth of the cutter; K - a correction factor for the quality of the material being processed n - spindle speed, rev / min. tx = 30,85 = 2,54; CP = 12.5; Syz = 0,240,75 = 0,342; Bu = 150; Dq = 1600.78 = 40.64; nw = 160-0,13 = 0,516; CMR = 1.12; Z = 10. PZ1 = 8699kg Define the cutting force to handle the end of the casting ?215 profits: tx = 30,85 = 2,54; CP = 12.5; Syz = 0,240,75 = 0,342; Bu = 215; Dq = 2500.73 = 56.29; nw = 160-0,13 = 0,516. PZ2 = 10,802kg Determine PZ3 tx = 30,85 = 2,54; CP = 12.5; Syz = 0,240,75 = 0,342; Bu = 150; Dq = 1600.78 = 40.64; nw = 160-0,13 = 0,516; Z = 10. PZ3 = 8699kg PZ1i PZ3- resultant forces. Determine the torque for PZ3po formula [13] KM = W f1r + W f2r [1 / sin (a / 2)] where: W - cutting force f1i f2- coefficients of friction force a - the installation angle prisms KM = 10802 * 0,16 * 107,5 + I0802 * 0, I6 * I07,5 [1 / sin (90/2)] = 545426,56 Determine the clamping force according to the formula W = KM / (f1r + f2r sin (a / 2)) = 545426.56 * 56/17 + 17,2 * sin (a / 2) For double acting cylinder at a pressure of rodless cavity [18] W = 0,785 * D2R h, where: D - diameter of the cylinder, mm P - air pressure in kg / cm2 h = 0,85 ? 0,90 efficiency cylinder From the formula can determine the diameter of the cylinder, if known W and P W = 17896n; == P 0,4 MPa From the formula W = 0,785 * D2R h, You can determine the diameter of the cylinder going to simplify the calculation, and the creation of the reserve force of the rule formula h efficiency, but what he saw requirement calculation force on the rod W is increased by 1.5 times and double-acting cylinder diameter is found from the equation 1,5W = 0,785 D2R, where D == 292,4mm Choosing an air cylinder to directory ? cylinder = 300 mm ? = 65 mm rod Determines the validity of the clamping force W = 0,785 D2R / 1.5 = 18840 H Determine the response time of the pneumatic cylinder according to the formula: Tc = (A ^ * lx) / (d20 * Vc), where: lx- length moves the piston design accessories d0- diameter vozduhoprivoda Vc- speed of the compressed air Tc = (300 * 60) / (82-180) = 1.5 sec 4 CALCULATION AND PRODUCTION PLAN AREA 4.1 Calculation of the number of production equipment and load it. Exhaust stroke - 6,88min. Release program 35000sht In mass production of the estimated amount of equipment is determined by the formula [7] Cp = Tsht * N / 60 Gd, where: Tsht- total processing time details N - release program details Gd- effective annual fund production time (4015chas). Think of Operations: 10 Operation milling Cp = 4.92 * 35000/60 * 4015 = 0.71, accept one machine. Determine the load factor K = 71%. 15 Operation Turning Cp = 4.09 * 35000/60 * 4015 = 0.59, accept one machine. The load factor K = 59%. 20 Operation automaton Cp = 5.62 * 35000/60 * 4015 = 0.81, accept one machine. The load factor K = 81%. 30 Operation automaton Cp = 5.29 * 35000/60 * 4015 = 0.76, accept one machine. The load factor K = 76%. 35 Operation aggregate Cp = 4.09 * 35000/60 * 4015 = 0.59, accept one machine. The load factor K = 59%. 40 Operation locksmith Cp = 3.48 * 35000/60 * 4015 = 0.5, take a sander. The load factor K = 50%. Average% loading equipment - 69%. All estimates are tabulated. Table 3 Estimates. Name of the operation time of the part number of machine utilization rate,% Rated A received 10 Milling 4.92 0.71 1 71 Turning 15 4.09 0.59 1 59 20 submachine 5.62 0.81 1 81 30 submachine 5.29 0.76 1 76 35 aggregate 4.09 0.59 1 59 Locksmith 40 3.48 0.5 1 50 The average load factor of equipment is determined by the formula DAC = (Sras / Sprinim) * 100% = 69%. 4.2 Selecting the required amount of conveyor technology In the shops and high-volume mass production are widely used electric lifting kranbalki controlled push-button remote control with sex shops, traveling cranes. For mechanization of technological processes used ropfgangi and conveyors for transport of intra and interdepartmental parts or pieces used transport and motorized vehicles, electric vehicles. To take the projected area mechanized forklift CH-63, in the amount of 4 pieces, mechanized trolley on rails, load capacity of 1.5 t and bridge crane lifting capacity of 5t. 4.3 Calculation of the number of main and auxiliary workers, engineers and employees The calculation of the number of workers by category. For this mode to be determined (T) at each operation according to the formula: [7] T = Tper * * Ref DRG, where T - period of service jobs (8.2 hours) Spr- taken jobs Kzg- load factor jobs for this operation. T1 = 1 * 8.2 * 0.71 = 5.82 T2 = 8.2 * 1 * 0.59 = 4.83 T3 = 1 * 8.2 * 0.81 = 6.64 T4 = 1 * 8.2 * 0.76 = 6.23 T5 = 8.2 * 1 * 0.59 = 4.83 T6 = 8.2 * 1 * 0.5 = 4.2 The number of production workers is given by: PCT = Tshk * N / 60 * GDR PCT where the number of workers of the profession and discharge Tshk- single-piece-calculation time for an operation; Gdr- actual annual fund of working time machine operator GDR = [(365-104-8) * 8.2 - 6.1] * KH, where 365 - the number of calendar days in the year; 104 - the number of days off per year, with a 5-day week; 8 - the number of public holidays; 8.2 - working hours; 6 - the number of pre-holiday days with a reduction of 1 hour working days Prince-factor considering the use of nominal fund of time due to absenteeism. Kn = (100 - CH) / 100 where CH losses due to absenteeism, leave 15 days Kn = (100 - 18) / 100 = 0.82 T = (365 - 104 -8) * 8.2 * 6.1 * 0.82 = 1930 (h) Think of Operations: 10 Operation milling PCT = 4.02 * 35000/80 * 1930 = 1.48, take two Milling 15 Operation Turning PCT = 4.02 * 35000/80 * 1930 = 1.23, take two turner 20 Operation automaton PCT = 4.02 * 35000/80 * 1930 = 1.7, take two turner. 30 Operation automaton PCT = 4.02 * 35000/80 * 1930 = 1.6, take two turners 35 Operation aggregate PCT = 4.02 * 35000/80 * 1930 = 1.23, take two driller. 40 Operation locksmith PCT = 4.02 * 35000/80 * 1930 = 1.05, machine operators perform locksmith work Basic operating accept 8. Adjuster - 1 person - 5 category; Transport Workers -1chelovek - 3razryad; Controller -1 people - 3 digit. Total received: 8 + 3 = 11 people. When mnogostanochnoy calculation of production workers work done with respect to a given number of machines, which can run one operating the profession. [1, 15] PCT = FdSpKz / GdrSm, where Fd- effective annual fund operating time of the production machine Cn taken the number of machines Kz- load factor machines Gdr- actual annual fund operating time machine operator Cm number of machines, which can work at the same time a worker The number of machines that can be operated by one worker equals See tma = tvp + / + tvn tvp + tper, wherein tma- continuous automatic machine and the time during which the machine can be operated without working tvn- support non-overlapping time tvp- support overlapping time on a single machine tper- time to move the worker from one machine to another. Cm = 3.4 + 0.95 / 0.95 + 0.42 + 0.5 = 2.15 Take 2 machine Then PCT = FdSpKz / GdrSm, PCT = 4015 * 2 * 0.59 * 0.81 / 1930 * 2 = 1.02, accept one person. For the operation - 15 machine gun - machine MK112 and operation - 20 machine gun - machine 1B284 take one working machine operator, for the operation - 30 machine gun - machine 1B284, for the operation - 35 aggregate - machine .1AM0443 Cm = 3.12 + 0.95 / 0.95 + 0.42 + 0.5 = 2.13 takes 2 machine. PCT = 4015 * 2 * 0.59 * 0.76 / 1930 * 2 = 1.01 accept one working machine operator. Total basic working on all transactions take 8 vspomogatelnyh- 3, adopted on 8 + 3 = 11chelovek. 4.4 CALCULATION production areas, Disposition sites. Total land area (Rob) consists of production (RPR) and auxiliary (RVSP) area. Rob RPR + = RVSP, Production area occupied by the main jobs, walkways, driveways. It is defined by RPR = S (P1 + P2) * Ref. where P1- specific area on a piece of equipment, m2 P2 specific area on the walkways and driveways; P2 = 6 m2 + 8 m2; Spr- number of similar machines; n - number of items. Secondary area, occupied by warehouses, determined RVSP = MLR + + Rkontr Rbyt., Rskl- where the area under the blank 15% of the production Rkontr- area checkpoint, 6% of the production Rbyt.- area of ??residential, office space The area of ??the checkpoint and the area of ??household, office space provided on the area of ??the shop. P = 14.69 + 5.29 + 6 + 6 + 6 + 9.81 + 30.86 + 6 = 100m2 Warehouse space blank RSK. zag. = Q * N * td / Tr * q * K where Q is the weight of the workpiece, kg N - number of items, pieces; TK-stock quantity (6days) Tp-working days (253) q - permissible load (load capacity of 1 M2 1.5 m); RSK. zag. = 37.7 * 35000 * 6/253 * 1.5 * 0.4 = 47 m2 RSK. children. = 27.4 * 35000 * 6/253 * 1.5 * 0.4 = 35m2 Total land area Rob. = 100 + 47 + 35 = 182 Vuch = 182 * 6 = 1092 m3 5 ORGANIZATIONAL PART
5.1 Organization of jobs and system maintenance. For each worker must be provided a convenient place, feel free to his actions during operation. The workplace should be secured area to accommodate tooling blanks. Shelves for storage of parts and workpieces to be such a height that the working comfortably and safely stow blanks and parts. Do not store the tool in the machine frame. Cupboards for tools and equipment must match the number of jobs and the shape of things to store which they are intended. Cleaning chips from machine tools and automatic transfer lines should be as mechanized. In the process map and commissioning etc. must be specified devices, cutting tools and measuring safety devices, transport, lifting means and methods to ensure safe operations. 5.2 Measures for the protection of health and safety Under the OSH should understand complex technical, sanitary and legal measures aimed at creating a safe and healthy working conditions. Safety industrial sanitation define such conditions in a production environment, which can not directly or indirectly lead to accidents, occupational diseases. Therefore, workers are required to strictly comply with all applicable safety regulations and industrial hygiene. The development and implementation of measures to create a safe and healthy working conditions is important to follow the sequence and complexity. You must first remove the factors harmful effects on the human body - the noise, unfavorable climate, air pollution in industrial premises, etc., and then proceed to the aestheticization of the production environment. To comply with the permissible mikrokliamticheskih conditions in the work area must be room in summer - natural ventilation, air conditioning; winter - hot air curtains and locks in the doorway of industrial premises. For the purity of the air at the site should be used forced-air ventilation. Measures to combat noise and vibration - the use of sound insulation for walls, the use of personal protective equipment, etc. To avoid injury when working on machine tools must be strictly adhered to the rules of TB. Moving and rotating parts of the machine must be closed reliable guards. Provide protective equipment (plastic screens, glasses) of the emitted chips. Workpiece and the tool must be secured. Organizational measures: quality and timely briefings on TB, the organization of social labor inspection, strengthening billboards, hanging posters on TB, TB corner of creation, the appointment of duty (in turn) safety on each shift. 5.3 Measures for fire protection Fire hazard plant belongs to the category "D" - processing incombustible substances and materials in the cold condition. To avoid fires must comply with the rules of fire safety. On the territory of the shop aisles, driveways, hatches wells should be free and not cluttered with materials, blanks, parts and production waste. Oily rags should be collected in a certain place constantly get out of the shop. Must be a fire escape plan, a sand box, fire-fighting equipment on the boards in the right amount and shall be easily accessible. You must have an emergency exit in case of fire. Must also be blocking electrical equipment. 5.4 Determination of annual need of materials, tools, energy and water Planning and accounting of balance of energy produced by the method. Energy balances of the plant divided by the nature and purpose (planning, reporting), by type of energy and facilities. Balances are developed on the basis of the relevant expenditure norms. Annual energy consumption in kWh is given by: Er = (Fs * Must * C * h * CWR) / KpsKm = 120 * 4015 * 2 * 0.5 / 0.96 * 0.85 = 59044 kW / h where: Must- installed capacity of electric equipment stock kW; Fd- valid fund operating time per shift in hours; C - the number of shifts per day of the equipment; h - equipment load factor of 0.75; Kvr- coefficient of simultaneous operation of the equipment (0.4 - 0.6); Kp.s.- coefficient taking into account losses in the network (0.95 - 0.97); KM efficiency motor (0.8 - 0.85). Need of the materials specified in the annual, quarterly and remarks sections and calculated on the basis of a given production program (taking into account the timing margin products in production) and progressive consumption rates of materials. The value of delivery (delivery) of each type of material is determined on annual basis according to the formula H = + By + Ilb He Oak, where: Therefore the need for the main production plants in the material of this kind and size in t; Pv- need service shops in the material of this kind and size in t; Oak remainder of this kind of material at the end of the planning period t; On-the remainder of this kind of material at the beginning of the planning period in t; determined by adding to it. The actual availability at the time of the plan expected receipt of materials to the end of the reporting period preceding the planned; of this amount shall be deducted the planned material consumption for the same period; shall be equal to the difference between the expected balance at the beginning of the planning period. When calculating the annual needs of the enterprise in the tool using one of three methods, namely: a) at application rates of the tool; b) the coefficients of the average equipment jobs; c) for the reporting and static data. In determining the need for instrument The consumption is necessary to determine the service life of the tool in hours Tsrpo the following formula: Toff = (L / l +1) * Tcm (1-b), where: L - value of the allowable wetting the cutting part of the tool, in mm; l - the value of the layer is removed in one regrinding, in mm; Tcm- resistant tool, ie the work it between two regrinds in hours; b - coefficient of random loss tool (b = 0,05 ? 0,10). Toff = (15/3 + 1) 0.5 * (1 - 0.05) = 2.85 (h) Number of cutting tools required to perform the annual program n - determined by the formula n = S (N * tm / Toff * 60) where: kDa number of types of parts to be processed by the tool; N - number of specific parts of the name, to be processed by the tool on the annual production program pcs .; tm- machining time specified name, which is used for the treatment of this instrument in min .; Tsr- tool life up to full deterioration in hours. Drills ? 23 n = S (35000 * 1.45 / 2.85 * 60) = 296 pcs Drills ? 14 n = S (35000 * 0.68 / 2.85 * 60) = 137 pcs Cutter n = S (35000 * 0.5 / 60 * 2.85) = 102 pcs Tap n = S (35000 * 0.11 / 60 * 2.85) = 23 units Mills n = S (35000 * 1.43 / 2.85 * 60) = 292 pcs 6. The economic part 6.1 VALUATION OF FIXED ASSETS The cost of building is determined by the formula RCH = Fo * 1.1 NS, where: Fo- total internal area of ??the plot [2] RCH = 180 1.1 6 35 = 41580 (rub.) / 2,079,000 tenge Calculating the cost of production equipment (take out of the consolidated statement of equipment) 113499 rubles. / 5674950 tenge Calculating the cost of Conveyor (take from the consolidated statement of equipment) 9410 rub. / 470,500 tenge Cost quickly wear out tools and equipment to accept the standard cost for one machine. The estimates take 50% wear. Machine GF 1400 560 50/100 = 280 rubles. MK 112 350 50/100 = 175 rubles. 1B284 350 50/100 = 175 rubles. 1AM0443 230 50/100 = 115rub Total cost: 280 + 175 + 175 + 175 + 115 = 920rub / 46000 tenge Cost of production equipment. Take 20rub per worker 20 * 8 = 160 rub. / 8000 tenge The cost of household equipment 20 * 8 = 160 rub. / 8000 tenge Table 4 - Summary of fixed assets Name of fixed assets The cost of fixed assets RUB / KZT Depreciation rate % Depreciation deductions-WIDE, RUB / KZT Building Basic equipment Handling equipment Tools and accessories Production equipment Household equipment Expensive tool 41580/2079000 383419/19170950 9410/470500 920/46000 160/8000 160/8000 1500/75000 3.0 14 16 20 12 12 50 1247/62350 54828/2741400 1562/78100 184/9200 20/1000 20/1000 750/37500 Total: 437 149 rubles. / 58612/2930600 23657450 tenge tenge 6.2. VALUATION OF MATERIAL This calculation is made on the basis of norms of material consumption per part to the cost of returnable waste, prices for transportation and procurement costs and programs. Determine the cost of the basic material for the annual [2]; M = (Pm Qm * * Ktz- q0 * P0) * N, wherein: the flow rate Qm- material preform kg; Pm- wholesale price for 1kg material RUB / KZT; Ktz- factor ordering costs; q0- mass return of waste to the workpiece, kg; P0- price for 1kg of returnable waste, kg; N - annual program, pc; M = (37.7 * 0.47 * 1.05 - 10 * 0.024) * 39 000 = 659572,79rub / 32978600 tenge 6.3. VALUATION low value of tools and accessories Costs associated with wear and repair of low value tools and equipment accounted for 40 rubles per 1 machine. Determine the cost of 5 machines: 40 x 5 = 200 rub. / 10000 tenge 6.4. VALUATION OF ALL KINDS OF ENERGY AND WATER The cost of electricity power: 3c = ClSNu Fs * * * By Ks / EC * Tg where: C1 cost of 1 kW / h (0.0051 rubles / 0,255tenge); Fd- total power of the engines on equipment kW; Fs-efficient fund operating time, hour; Ks-average load factor of equipment (0.88); K - coefficient of simultaneous operation of the equipment (0.74 0.75); es- efficiency of the machine (the average efficiency of electrical equipment (0.85); Tg- loss rate in the network (0,95); 3c = 0,0051 * 120 * 4015 * 0.88 * 0.7 / 0.85 * 0.95 = 1874.45 rubles / 93722.5 tenge. Costs for compressed air [3]; REM = * Qczh CSF, where: Tsszh- cost 1m3szhatogo air (0,002 rubles / 0,1tenge); Qszh- annual consumption of compressed air, m3; Qszh = Fs * Ks * Sob * q ', where: Sob = 5 using blasting; q = 1 m3 / h - compressed air consumption for 1 machine. Qszh = 0.88 * 4015 * 5 * 1 = 17766 m3; VSL = 0.002 * 17,766 = 35.33 rub. / 1248,21tenge Consumption of energy and fuel for household needs. The cost of electricity for lighting [2] SEA = C1 * W, where: C1 cost of 1 kW / h (0,0051rub / 0,26tenge); W -Annual need Kilowatt [2]; W = dcp * F * T / 1000? where: dcp- Medium electricity consumption for lighting 1m2; F - land area (182 m2); T - duration of light per year, with two-shift operation (2630 hours); 1.05 coefficient takes into account the 5% loss at daylight W = 25 * 1.05 * 182 * 2630/1000 = 11966.5 kW SEA = 0.0051 * 11 * 966.5 = 61.02 rub. / 3051tenge Expenditure on steam for heating [2]; Sn = C * Wp, where: Cn value of 1 ton of steam (4,66rub / 233tenge); Wp- annual demand of steam on the machine; Wp = qn * V * TGI / g * 1000 where: qn- fuel consumption by 1 m3zdaniya (25,435 kcal / h); \ / - Internal volume of the building; Tot- duration of the heating season (4320chas); g - heat of vaporization (540 kcal / h). Wp = 25 * 1092 * 4320/540 * 1000 = 218 tonnes Sn = 4.66 * 218 = 1016 rubles / 50800 tenge. Water consumption for household needs: Sre households. = St. * Qhoz, where: Sv.- cost of 1 m2vody (10 kopecks); Qhoz- annual demand for water for domestic and economic needs; Qhoz = qv * TV * Cr / 1000 where: QB-rate of water flow per employee (75 l); TV number of working days 1 working (253 days); Kp number of employees at the site (10). Qhoz = 75 * 253 * 10/1000 = 189.75 m3; Sre. host = 0.1 * 189.75 = 18.97 rubles / 948.5 m. Water consumption for industrial needs: St. Flowers * QB = Ks * * Z, where: C - 1 m3vodoprovodnoy cost of water (0.10 rubles / 5tenge); QB-annual water consumption for 1 machine (25 m3); Z- number of shifts; Kz- equipment load factor St. = 0.10 * 25 * 5 * 0.85 * 2 = 21.25 rubles / 1062,5tenge. 6.5. Determination of the wage fund Definition of the payroll of all categories of workers: 1. Calculation of payroll basic working [2] RSD = Tg tshk * * N / 60, where: tshk- single-piece-calculation time T - flat rate according to the category Machinists work in a team and perform locksmith work. Total machinists 8 people, they substitute for each other when dvusmennoy work the first shift 4 people and the second shift 4 people. Determining the wage, pay, consider mnogostanochnoe service: The calculation of Operations: 10 Milling operation Tg = 0.67 rubles. RSD = 0.67 * 4.92 * 35000/60 = 1992.9 rubles / 99645tenge. tshk = 4.92 min 1. The calculation of premiums payroll ZPpr ZPst * = 30/100 = 1992.9 * 30/100 = 597.87 rubles / 29893tenge 2. The main fund s / n with the payment of bonuses 1992.9 + 597.87 = 2590.77 rubles / 129538,5tenge 3. Supplementary Fund CLP = 10% ZPdop = 2590.77 * 10/100 = 259.07 rubles / 12953,5tenge 4. The main fund plus an additional fund ZPosn = 2590.77 + 259.07 = 2849.84 rubles / 142492tenge 5. The waist ratio 15% R = 2849.84 * 15/100 = 427.476 rubles / 21374tenge 6. The total payroll for the year ZPgod = 2849.84 + 427.476 = 3277.31 rubles / 163865.5 tenge 40 operation locksmith Tg = 0.67 = 3.48 rubles tshk min RSD = about 67 x - 3.48 * 35000/60 = 2030 rubles / 101500 tenge I. Calculation of premiums from payroll ZPpr = 2030 * 30/100 = 609 rubles / 30450 tenge 2.Core payroll, taking into account payment of premiums 2030 + 609 = 2639 rubles / 131950 tenge 3. Supplementary Fund K = 10% ZPdop = 2639 * 10/100 = 263 rubles / 13150 tenge 4. Supplementary Fund plus the main fund 2639 + 263 = 2902 rubles / 145,100 tenge 5. The waist ratio 15% R = 2902 * 15/100 = 435.30 rubles / 21765 tenge The total payroll for the year ZPgod = 2902.15 + 435.30 = 3337.45 rubles / 166872.5 tenge The calculation of basic operating fund at mnogostanochnom service. Step 15 and 20 turning machine gun performs one work in the first shift, 4 bits, 4 bits and machine operator the second shift. Payroll apply a factor of 0.7 mnogostanochnogo for maintenance. 15 Operation Turning 20 machine gun operation He = 0.67 rubles / 33,5tenge He = 0.67 rubles / 33.5 tenge RSD = 0.67 * 4.09 * 35000/60 = 1598.5 rubles / 79925 tenge; RSD = 0.67 * 5.62 * 35000/60 = 2196.48 RUB / KZT 109,824; RSD = (1598.5 + 2196.48) * 70/100 = 2655.08 rubles / 132754 tenge 1.Raschet premium payroll ZPpr = 2655.08 * 30/100 = 796.52 rubles / 39826 tenge; 2. The main fund s / n with the payment of bonuses ZP0 = 2655.08 + 796.52 = 3451.6 rubles / 172,580 tenge; 3. Supplementary Fund CLP = 10% ZPdop. = 345.16 * 10/100 = 345.16 rubles / 17258 tenge 4. The main fund plus an additional fund CP = 3451.6 + 345.16 = 3796.76 rubles / 189,838 tenge 5. The waist ratio 15% R = 3796.76 * 15/100 = 569.51 rubles / 28475.5 tenge 6. The total payroll for the year ZPgod = 3736.76 + 569.51 = 4366.27 rubles / 218313.5 tenge 30-machine operation and 35 aggregate operation He = 0.67 rubles / 33.5 = 0.67 tenge That RUB / KZT 33.5 wk = wk = 5.29 m 4.09 m RSD = 2067.5 rubles / RSD = 103375 KZT 1,598.5 rubles / 79925 tenge RSD = (2067.5 + 1598.5) * 70/100 = 2566.2 rubles / 128,310 tenge 1. Calculation of the Prize Fund RFP Zppr = 2566.2 * 30/100 = 769.86 rubles / 38493 tenge 2. The main fund with the payment of bonuses 2566.2 + 769.86 = 3336.06 rubles / 166,803 tenge 3. Supplementary Fund CLP = 10% ZPdop. = 3336.06 * 10/100 = 333.6 rubles / 16680 tenge 4. Supplementary Fund plus the main fund 3336.06 + 333.6 = 3669.66 rubles / 183,483 tenge 5.Poyasnoy coefficient of 15% R = 3669 * 15/100 = 550.44 rubles / 27522 tenge 6. The total payroll for the year ZPgod = 3669.66 + 550.44 = 4220.10 rubles / 211,005 tenge The total payroll for all transactions: CP = 3277.31 + 3337.45 + 4366.27 + 4220.10 = 15201.13 rub / 760056.5 tenge RFP one machinist average ZPmest.st. = 15,201.13: 8: 12 = 158.34 rubles / 7917 tenge Calculating payroll auxiliary workers: I. Calculation of premiums from the total wage bill ZPpr = 1287 * 30/100 = 389.36 rubles / 19468 tenge for the adjuster ZPpr = 1041.21 * 30/100 = 312.36 rubles / 15618 tenge for the controller and transport workers. 2.0snovnoy payroll, taking into account the payment of premiums 1287 + 389.36 = 1676.36 rubles / 83 818 tenge for the adjuster. 1041.21 + 312.36 = 1353.57 rubles / 67678 tenge for the controller and transport workers. Z. Supplementary Fund CLP = 10% 1676.36 * 10/100 = 167.63 rubles / 8381.5 tenge for the adjuster. 1353.57 * 10/100 = 135.35 rubles / 6767.5 tenge for the controller and transport workers. 4. Main Fund plus an additional fund 1676.36 + 167.63 = 1843.99 rub. / 92199.5 tenge for the adjuster 1353.57 + 135.35 = 1488.92 rub. / 74 446 tenge for the controller and transport workers. 5. The waist ratio 15% 1843.997 * 15/100 = 276.59 rub. / 13829.5 tenge for the adjuster. 100 1488.92 * 15/100 = 223.33 rub. / 11166.5 tenge for the controller and transport workers. 6. The total payroll for the year 1843.99 + 276.59 = 2120.59 rub. / 106,029 tenge for the adjuster. 1488.92 + 223.33 = 1712.25 rub. / 85612.5 tenge for the controller and transport workers. 7 .Srednemesyachnaya salary: one working 2120.59 12 = 176.71 rubles. / 8835 tenge adjuster. 1712.25: 12 = 142.68 rub. / 7134 tenge Comptroller and transport workers. Annual payroll on site Zpgod = ZPosn. slave. + ZPvsp., ZPgod = 15201.13 2120.59 2 '= 1712.25 20746.22 rub / 1,037,311 tenge. 6.6. Estimated shop expenses Items of expenditure The amount of KZT. 1. The basic wage A) support workers 2. Social security contributions 14% of the total wages 3. The cost of maintenance of buildings, structures A) electricity for lighting B) steam for heating B) water for domestic use 4. The cost of maintenance and operation of equipment A) power electricity B) compressed air 5. Depreciation of equipment, vehicles and expensive tooling 6. The costs of repairs and maintenance of equipment 7. The costs of depreciation and maintenance of low-value tools and equipment 8. The cost of auxiliary materials 9. Depreciation of production areas (3%) 10. Costs for the protection of health and safety 11. Costs of invention and rationalization 277254.5 145223.5 3051 50800 948.5 93722.5 1766.5 765900 397250 212500 20000 58830 16500 11000 Total: 2053246tenge 6.7. Calculation of economic efficiency of projects and the level of profitability Shop cost was (on an annual program): 659572 + 56266 + 2128 = 717794.21 rub. / 35889710.5 tenge Works general expenses accounted for 80% of the basic salary of workers 15201.13 * 80/100 = 12160.90 rub. / 608,045 tenge Production cost is the sum of the cost of parts and works general expenses Ref = 729,955.11 rubles / 36497755.5 tenge. Non-production costs amount to 5% of the production cost - 36497,75rub / 1824887.5 m. Total cost is the sum of cost of production and non-productive costs Cn = 766,452.86 rubles / 38,322,643 tenge. The company's profit is 15% of the total cost P = 114967,92rub / 5748396. tenge The wholesale price of the company is the sum of the total cost and profit of the enterprise Tsopt. 881420,78rub = / 44071000 tenge. Level of profitability: P / Ep = 114,967.92 / 766,452.86 * 100 = 15% Output in rubles 881,420.78 rubles / 44,071,000 tenge. Capital productivity = TP / Stand. osn.f = 881,420.78 / 437,149 = 2.01 = Capital-stoim.osn.f. / Number of the slave. in Naib. cm. = 437149/7 = = 62450 rubles / 3,122,500 tenge Shift factor = number of slave. Ouch. / number of the slave. in Naib. cm. KSM = 11/7 = 1.6 Output per worker 1 = TP / Crab = 881,420.78 / 11 = = 80129 rubles / 4,006,450 tenge. 6.8.TEHNIKO-ECONOMIC INDICATORS OF SITE The name of indicators Unit measurement Indicators The annual program of manufacture of the product Same The total number of employees, including: mainly workers auxiliary workers The average wage group main working Payroll on site Number of equipment Total cost of equipment The total capacity of the equipment Average loading equipment The production area of ??the site Unit cost of manufactured products Profit Level of profitability Capital productivity Fondovooruzhennsot Pcs. Rub. Pers Pers Pers - rub. Pcs. rub. kw % m 2 rub. rub. % rub. 35000 881,420.78 11 8 3 4 20746.22 5 383419 120 69 182 20.50 114,967.92 15 2.01 62450 REFERENCES 1. Bogolyubov O.K., Warriors AV Drawing M .: Engineering, 1984,304s. 2. Resurrection BV, Palamarchuk AS Directory Economist engineering enterprise. M..Mashinostroenie, 1971. Z.Gorbatsevich AF, Shkred VA, Course design in mechanical engineering. M .: Higher School, 1983. .. 4.Dobrschnev IS Course design on the subject of "Mechanical Engineering" ..: Engineering, 1985,184s. 5.Medovoy IA Drozdov YI, Gorodetskaya II Gages threaded cylindrical. M: Mechanical Engineering, 1984. 6.Nefedov NA Diploma design in engineering college. M .: Higher School, 1976. 7.0bschemashinostroitelnye standards cutting conditions for technical regulation works on machine tools. M: Mechanical Engineering, 1967, p.1. 8.0bschemashinostroigepnye standards temporary support maintenance of the workplace and set-closing for technical regulation of machine work. M: Mechanical Engineering, 1974. 9.Polivanov PI Table to calculate the mass of details and materialov.M.: Mechanical Engineering, 1975. 10.Rukovodstvo on course design metal instrumentov.M.: Mechanical Engineering, 1986. 11.Semenchenko II Matyushin V.M7 Sakharov GN Design of cutting tools. M.'Mashgiz, 1962. 12.Spravochnik technologist Machinist in 2 volumes / Ed. AG Kosimova M. Machinery, 1985,496s. 13.Spravochnik technologist Machinist / Ed. AN Malov. Ed. Third, the slave pen. M .: Machine structure t.2,1972, 720c. 14. Gamrat Kurek-LI The economic rationale for graduation projects. M .: Higher School, 1974,19Ss. 15.Shatin VP Shatin Yu Directory êîíñòðóêòîðà-èíñòðó-ìåíòàïüùèêà.Ì.:Ìàøèíîñòðîåíèå,1975.456ñ. 16.Ekonomika, organization and planning of engineering production. M .: Higher School, 1973. 17. MA Anserov tools for machine tools Mechanical Engineering, 1966 |
Àâ³àö³ÿ ³ êîñìîíàâòèêà |

© 8ref.com - óêðà¿íñüê³ ðåôåðàòè